Solve by cross multiplication method:
4u-v=4 , 3u+2v=14
Answers
Answered by
8
4X - Y = 4 .............(1)
3X + 2Y = 14.........(2)
HERE,
A1 = 4 , A2 = 3 , B1 = -1 , B2 = 2 , C1 = -4 , C2 = -14.
THEREFORE BY CROSS MULTIPLICATION METHOD,
X/ B1C2-B2C1 = Y/C1A2-C2A1 = 1/A1B2-A2B1.
X/ (-1× -14) -( 2×-4) = Y/(-4×3)- (-14×4) = 1/(4×2) × (3×-1) .
. SOLVE YOU WILL GET THE VALUE OF X AND Y..
3X + 2Y = 14.........(2)
HERE,
A1 = 4 , A2 = 3 , B1 = -1 , B2 = 2 , C1 = -4 , C2 = -14.
THEREFORE BY CROSS MULTIPLICATION METHOD,
X/ B1C2-B2C1 = Y/C1A2-C2A1 = 1/A1B2-A2B1.
X/ (-1× -14) -( 2×-4) = Y/(-4×3)- (-14×4) = 1/(4×2) × (3×-1) .
. SOLVE YOU WILL GET THE VALUE OF X AND Y..
RRRSROHITSAHU1234:
in my book it is solved by x,y,1
Answered by
5
I hope this answer will help you;:-}♡
■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■
○●○●○●○●○|○●○●○●○●○●○●○●○●○●○●○●○●○●○●○●○|○●○●○
Thanks
Attachments:
Similar questions
Science,
7 months ago
Hindi,
7 months ago
Social Sciences,
1 year ago
Math,
1 year ago
India Languages,
1 year ago
Math,
1 year ago