Math, asked by bhargu, 1 year ago

solve by elimination.
5x+4y-4=0 and x-20=12

Answers

Answered by Riasha

x-20=12
Therefore, x=12+20
=32
Now, 5x+4y-4=0
Therefore, 5x+4y=4
On substituting x with 32 we get,
5*32+4y=4
160+4y=4
4y=4-160
4y=-156
y= -39
Ans=> x=32, y =-39

Riasha: pls mark as best answerbpls pls pls :)

thinkdifferent: But I think he has written the question wrongly

Riasha: You mean it should have been a simultaneous equation?

Riasha: If the question was this it could be solved, see my solution. :)

bhargu: riasha can u pl. answer my some more questions.

Riasha: yeah why not. say?

bhargu: i have posted by questions

Riasha: K.

bhargu: solve by substitution.
43x+67y=-24 and 67x+43y=24

Answered by vivek2001

5x+4y-4=0 and x-20=12
x-20=12 or x=12+20 or x=32
5x+4y-4=0
=>5*32+4y-4=0
=>160-4+4y=0
=>156+4y=0
=>4y=-156
=>y=-156/4
=>y=-39-----------(3)
putting this value of (3) in (2) we'll get the value of x.

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solve by elimination.5x+4y-4=0 and x-20=12

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solve by elimination.
5x+4y-4=0 and x-20=12