Solve by elimination ax+a2y=an and abx-b2y=bc
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Step-by-step explanation:
(ax+a²y = an)×b
(abx -b²y=bc)×-1
abx+a²by =abn
-abx+b²y= -bc
=>a²by +b²y = abn-bc
=>by(a²+ b) = b(an-c)
=> y = b(an-c) / (a² + b)
Further, put the value of y in first equation to find x
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