Question

Solve by elimination method 3x-y=3; 9x-3y=9

Answer 1

3x-y=3 -----(1)

9x-3y=9------(2)

x= 3+y / 3 

9 ( 3+y / 3) = 9 

27+9y /3 = 9

27 +9y = 9*3

9y = 27-27

9y =0

y=0/9 

y=0

(put value of y in 1st equation)

3x-y=3

3x-0=3

3x=3

x=3/3

x = 1

(1,0)

therefore, value of x and y by substitution method is 1 and 0

Answer 2

Answer:

Explanation:

Given :-

3x - y = 3                

9x - 3y = 9      

Solution :-

⇒ 3x - y = 3 ... (i)                  

⇒ 9x - 3y = 9 ... (ii)                  

From equation (i), we get                  

⇒ y = 3x - 3 ... (iii)                  

Putting this value in equation (ii), we get                  

⇒ 9x - 3(3x - 3) = 9                  

⇒ 9x - 9x + 9 = 9                  

⇒ 9 = 9    

           

Hence, This is always true.