solve by elimination or substitution method Qno 23 25
please solve for me fast guyzz..... guNna sleep as well
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Anonymous:
Hi, there.
resend, i have a solution
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☺here is your answer☺
23). a/x-b/y =0
so, a/ x = b/y
= now , ab²/x +a²b/y
= b³/ y + a²b/y = a² + b²
b³ + a²b /y = a²+b²
b ( a²+b²) /y = ( a²+b²)
so, y = b
hence , x = a
25.) we have 3 eq. of equal sides -
so, x + 3y = 3x+2y-2
2 = 2x -y ----(1)
⭐similarly we can foam other equation -
= 3y/2 - 3 = x -----(2)
⭐by solving , 1& 2
we get -
y = 4 & x = 3 answer...
⭐☺HOPE THIS WAS HELPFUL FOR U✨⭐
23). a/x-b/y =0
so, a/ x = b/y
= now , ab²/x +a²b/y
= b³/ y + a²b/y = a² + b²
b³ + a²b /y = a²+b²
b ( a²+b²) /y = ( a²+b²)
so, y = b
hence , x = a
25.) we have 3 eq. of equal sides -
so, x + 3y = 3x+2y-2
2 = 2x -y ----(1)
⭐similarly we can foam other equation -
= 3y/2 - 3 = x -----(2)
⭐by solving , 1& 2
we get -
y = 4 & x = 3 answer...
⭐☺HOPE THIS WAS HELPFUL FOR U✨⭐
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