Solve by factorisation method.

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2
Answer:
x^2+2x-160=0
a=1,b=2,c=-160
d=b^2-4ac
d=(2)^2-4*1*-160
d=4-4*-160
d=4-640
d=-636
d<0
therefore roots will not existed
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Answered by
1
Answer:
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