Solve by factorising:-
From Quadratic Equation
Standard:- 10
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Answered by
5
Given Equation is 2x^2 - x - 6 = 0
= > 2x^2 + 3x - 4x - 6 = 0
= > x(2x + 3) - 2(2x + 3) = 0
= > (x - 2)(2x + 3) = 0
= > x = 2, -3/2.
Hope this helps!
= > 2x^2 + 3x - 4x - 6 = 0
= > x(2x + 3) - 2(2x + 3) = 0
= > (x - 2)(2x + 3) = 0
= > x = 2, -3/2.
Hope this helps!
siddhartharao77:
:-)
Answered by
5
Hey!!!!
Difficulty Level : Below Average
Chances of being asked in Board : 30%
_________________
Let's factorize
=> 2x² - x - 6 = 0
By middle term splitting method
=> 2x² - 4x + 3x - 6 = 0
=> 2x(x- 2) + 3(x - 2) = 0
=> (x - 2)(2x + 3) = 0
Thus
=> x = 2 or x = - 3/2
________________
Hope this helps ✌️
Difficulty Level : Below Average
Chances of being asked in Board : 30%
_________________
Let's factorize
=> 2x² - x - 6 = 0
By middle term splitting method
=> 2x² - 4x + 3x - 6 = 0
=> 2x(x- 2) + 3(x - 2) = 0
=> (x - 2)(2x + 3) = 0
Thus
=> x = 2 or x = - 3/2
________________
Hope this helps ✌️
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