solve by factorization:- 4x²-4a²x+(a⁴-b⁴=0
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Given 4x2-4a2x (a4-b4)=0
4x[x - a2 (a4 - b4)] = 0
4x = 0 or [x - a2 (a4 - b4)] = 0
Therefore, x = 0 or x = a2 (a4 - b4)
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4x[x - a2 (a4 - b4)] = 0
4x = 0 or [x - a2 (a4 - b4)] = 0
Therefore, x = 0 or x = a2 (a4 - b4)
If useful pls mark me as brainliest.
tambesanket200p69bs7:
wrong answer
why
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