Question

Solve by factorization method
1.(x-4) (x+2)=0
please help me to find this out​

Answer 1

Answer:

$finally \: x = - 2 \: and \: 4$

Step-by-step explanation:

${x}^{2} + 2x - 4x - 8 = 0 \\ {x}^{2} - 2x - 8 = 0 \\ {x}^{2} - 4x + 2x - 8 = 0 \\ x(x - 4) + 2(x - 4) = 0 \\ (x + 2)(x - 4) = 0 \\ hence \: x = - 2 \: and \: 4$MARK ME BRAINLIEST PLS...

Answer 2

Answer:

(x-4)(x+2)=0

x(x+2) - 4(x+2) = 0

x² + 2x - 4x + 8 = 0

x² - 2x + 8 = 0

x² - 4x + 2x +8 = 0

x(x-4) + 2(x+4)=0

(x+2)(x+4)=0

Step-by-step explanation: