Question

Solve by formula: (-b±√(b²-4ac))/2a

question : x² - (1 + √3)x + √3 = 0

Answer 1

$a {x}^{2} + bx + c = 0 \\ x = \frac{ - b + | \sqrt{ {b}^{2} - 4ac } | }{2a} \\ here \\ a = 1 \\ b = - ( \sqrt{3} + 1) \\ c = \sqrt{3} \\ x = \frac{( \sqrt{3} + 1) + | \sqrt{ {( \sqrt{3} + 1) }^{2} - 4 \sqrt{3} } | }{2} \\ x = \frac{( \sqrt{3} + 1 + | \sqrt{3} - 1| }{2} \\ x = \sqrt{3} \\ x = 1$

hope it helps