Question

solve by gauss jordan method 2x-3y+z=-1
x+4y+5z=25
3x-4y+z=2​

Answer 1

Answer:

I hope it helps you.

Step-by-step explanation:

By Gauss Jordan method we get

⎡⎣⎢1234−3−4511⎤⎦⎥ ⎡⎣⎢xyz⎤⎦⎥ = ⎡⎣⎢25−12⎤⎦⎥

By R2-2R1 and R3-3R1

⎡⎣⎢1004−11−165−9−14⎤⎦⎥ ⎡⎣⎢xyz⎤⎦⎥ = ⎡⎣⎢25−51−73⎤⎦⎥

-R3 and -R2, 16R2 and 11R1

⎡⎣⎢10041761765144154⎤⎦⎥ ⎡⎣⎢xyz⎤⎦⎥ = ⎡⎣⎢25816803⎤⎦⎥

R3-R2 and (1/16)R2

⎡⎣⎢10041105910⎤⎦⎥ ⎡⎣⎢xyz⎤⎦⎥ = ⎡⎣⎢2551−13⎤⎦⎥

R2-(9/10)R3 and R1-(1/2)R3

⎡⎣⎢10041100010⎤⎦⎥ ⎡⎣⎢xyz⎤⎦⎥ = ⎡⎣⎢63/2627/10−13⎤⎦⎥

R1-(4/11)R2, (1/11)R1 and (1/10)R3

⎡⎣⎢100010001⎤⎦⎥ ⎡⎣⎢xyz⎤⎦⎥ = ⎡⎣⎢8.75.7−1.3⎤⎦⎥

Hence x = 8.7, y = 5.7, z = -1.3.