Solve by half reaction method
Answers
Answer:
It is given that aqueous sodium hydroxide (NaOH) solution is added to copper sulphate solution (CuSO₄) , and forms a bluish white precipitate i.e. Copper Hydroxide [Cu(OH)₂] .
Another product, which is formed in this reaction is aqueous solution of Sodium Sulphate (Na₂SO₄) .
NaOH + CuSO₄ → Cu(OH)₂ + Na₂SO₄
[skeletal equation]
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On observing the above equation carefully, we will understand that the equation will be balanced if we multiply "NaOH" on the reactant side with 2 .
2NaOH + CuSO₄ → Cu(OH)₂ + Na₂SO₄
[balanced equation] .
The obtained balanced equation will be more informative if we add "symbols of physical states" of the reactants and the products. So, here we write it :-
2NaOH (aq) + CuSO₄ (aq) → Cu(OH)₂ (s) + Na₂SO₄ (aq)