Question

solve by matrix ? how to

Answer 1

hey dear
hope it helps u
and hope you understand

Answer 2

$\huge \underline{ \tt{ \red{Q}} \tt{ \green{U}} \tt{ \blue{E}} \tt{\orange{S}} \tt{ \pink{T}} \tt{ \purple{I}} \tt{ \red{O}} \tt{\green{N }}}:-$

Find the value of x and y if

$\left[ \begin{array}{c c } \sf x + 10& \sf {y}^{2} + 2y \\\\ \sf \: 0& \sf \: - 4 \end{array} \right] = \left[ \begin{array}{c c } \sf 3x + 4& \sf 3 \\\\ \sf \: 0& \sf \: {y}^{2} - 5y \end{array} \right]$

$\huge \underline{ \tt{ \red{S}} \tt{ \green{O}} \tt{ \blue{L}} \tt{\orange{U}} \tt{ \pink{T}} \tt{ \purple{I}} \tt{ \red{O}} \tt{\green{N }}}:-</p><p>$

$: \longrightarrow\left[ \begin{array}{c c } \sf x + 10& \sf {y}^{2} + 2y \\\\ \sf \: 0& \sf \: - 4 \end{array} \right] = \left[ \begin{array}{c c } \sf 3x + 4& \sf 3 \\\\ \sf \: 0& \sf \: {y}^{2} - 5y \end{array} \right] \\ \\ \\ : \longrightarrow \sf x + 10 = 3x + 4 \\ : \longrightarrow \sf x - 3x = 4 - 10 \\ : \longrightarrow \sf \cancel - 2x = \cancel- 6 \\ \\ : \longrightarrow \sf x = \frac{ \cancel{6} ^{3} }{ \cancel{2}} \\ \\ \boxed{ \blue{: \longrightarrow \sf x = 3}} \\ \\ \\ \\ : \longrightarrow \sf {y}^{2} + 2y = 3 \\ : \longrightarrow \sf {y}^{2} + 2y - 3 = 0 \\ : \longrightarrow \sf {y}^{2} + 3y - y - 3 = 0 \\ : \longrightarrow \sf y(y + 3) - 1(y + 3) = 0 \\ : \longrightarrow \sf (y - 1)(y + 3) = 0 \\ \\ \boxed{ \blue{ : \longrightarrow \sf y = 1 \: \: or \: \: y = - 3}}$

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