Math, asked by Chiraglalwani, 1 year ago

Solve by quadratic formula 16 X square - 27 x minus 10 =0

Answers

Answered by Destroyer48
1
16x²- 27x- 10= 0
16x²- 32x+ 5x- 10= 0
16x(x-2) +5(x-2)= 0
(x-2)(16x+5)= 0

x= 2
x= -5/16

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Answered by HarishAS
1
Hi friend, Harish here.

Here is your answer:

The general form of quadratic equation is ax² + bx +c.

We have an expression, 16x² - 27x -10.

Where , a = 16, b = -27 , c = -10.

We know that,

x=  \frac{-b \±  \sqrt{b^{2} - 4ac} }{2a}

⇒  \frac{-(-27) \±  \sqrt{(-27)^{2} - 4 (16)(-10)} }{2\times 16}

⇒  \frac{27\±  \sqrt{729+640} }{32} =  \frac{27\±  \sqrt{1369}  }{32}= \frac{27\± 37}{32} = \frac{64}{32} = 2  

Another value is :

 \frac{27-37}{32} =  \frac{-10}{32} = \frac{-5}{16}

Therefore these two values of x. " 2  &  -5/16 " .
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Hope my  answer is hepful to you
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