Question

solve by reducible method 32/x-y+36/x+y=7,40/x-y+48/x+y=9​

Answer 1

Answer:

:3(2x+y)=7xy,3(x+3y)=11xy

Divide both sides by xy

xy

6x+3y

=7,

xy

3x+9y

=11

y

6

+

x

3

=7,

y

3

+

x

9

=11

Let u=

x

1

,v=

y

1

then the above equations becomes

6v+3u=7 ......(1) and 3v+9u=11 ....(2)

Eqn(1)−2×(2)

⇒6v+3u−6v−18u=7−22

⇒−15u=−15 or u=1

Substitute the value