solve by reducing them to a pair of linear equations
pls do it fast
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please please please urgent
Answers
Step-by-step explanation:
Given -
1/2x + 1/3y = 2
1/3x + 1/2y = 13/6
To Find -
- Value of x and y
Now,
1/2x + 1/3y = 2
→ 3y + 2x/6xy = 2
→ 3y + 2x = 12xy ...... (i)
And
1/3x + 1/2y = 13/6
→ 2y + 3x/6xy = 13/6
→ 2y + 3x = 13xy ........ (ii)
Now, From (i) and (ii), we get :
[ 3y + 2x = 12xy ] × 2
[ 2y + 3x = 13xy ] × 3
→ 6y + 4x = 24xy
6y + 9x = 39xy
(-) (-) (-)
______________
-5x = -15xy
→ y = 1/3
Now,
Substituting the value of y on (i), we get :
3y + 2x = 12xy
→ 3×1/3 + 2x = 12x × 1/3
→ 1 + 2x = 4x
→ 2x = 1
→ x = 1/2
Hence,
The value of x is 1/2 and y is 1/3
- (1/2)x + (1/3)y = 2
- (1/3)x + (1/2)y = 13/6
- Value of x and y
(1/2)x + (1/3)y = 2
3y + 2x/6xy = 2
3y + 2x = 12xy. ..(1)
(1/3)x + (1/2)y = 13/6
2y + 3x/6xy = 13/6
2y + 3x = 13xy. ..(2)
[3y + 2x = 12xy] × 2
[2y + 3x = 13xy] × 3
6y + 4x = 24xy
6y + 9x = 39xy
-5x = -15xy
y = 1/3
3y + 2x = 12xy
3 × 1/3 + 2x = 12xy
1 + 2x = 4x
2x = 1
x = 1/2