Math, asked by SGS126, 8 months ago

solve by reducing them to a pair of linear equations


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Answers

Answered by TrickYwriTer
4

Step-by-step explanation:

Given -

1/2x + 1/3y = 2

1/3x + 1/2y = 13/6

To Find -

  • Value of x and y

Now,

1/2x + 1/3y = 2

→ 3y + 2x/6xy = 2

→ 3y + 2x = 12xy ...... (i)

And

1/3x + 1/2y = 13/6

→ 2y + 3x/6xy = 13/6

→ 2y + 3x = 13xy ........ (ii)

Now, From (i) and (ii), we get :

[ 3y + 2x = 12xy ] × 2

[ 2y + 3x = 13xy ] × 3

→ 6y + 4x = 24xy

6y + 9x = 39xy

(-) (-) (-)

______________

-5x = -15xy

y = 1/3

Now,

Substituting the value of y on (i), we get :

3y + 2x = 12xy

→ 3×1/3 + 2x = 12x × 1/3

→ 1 + 2x = 4x

→ 2x = 1

x = 1/2

Hence,

The value of x is 1/2 and y is 1/3

Answered by silentlover45
1

  \huge \mathfrak{Answer:-}

\large\underline\mathrm{The \: value \: of \: x \: is \: 1/2 \: and \: y \: is \: 1/2.}

\large\underline\mathrm{Given:-}

  • (1/2)x + (1/3)y = 2
  • (1/3)x + (1/2)y = 13/6

\large\underline\mathrm{To \: find}

  • Value of x and y

\large\underline\mathrm{Solution}

\implies (1/2)x + (1/3)y = 2

\implies 3y + 2x/6xy = 2

\implies 3y + 2x = 12xy. ..(1)

\large\underline\mathrm{and}

\implies (1/3)x + (1/2)y = 13/6

\implies 2y + 3x/6xy = 13/6

\implies 2y + 3x = 13xy. ..(2)

\large\underline\mathrm{Now,}

\large\underline\mathrm{Eq. \: (1) \:  × \: 2 \: and \: Eq. \: (2) \: × \: 3. we \: get.}

\implies [3y + 2x = 12xy] × 2

\implies [2y + 3x = 13xy] × 3

\implies 6y + 4x = 24xy

\implies 6y + 9x = 39xy

\implies -5x = -15xy

\implies y = 1/3

\large\underline\mathrm{now,}

\large\underline\mathrm{putting \: the \: value \: of \: y \: on \: Eq. \: (1)}

\implies 3y + 2x = 12xy

\implies 3 × 1/3 + 2x = 12xy

\implies 1 + 2x = 4x

\implies 2x = 1

\implies x = 1/2

\large\underline\mathrm{hence, }

\large\underline\mathrm{The \: value \: of \: x \: is \: 1/2 \: and \: y \: is \: 1/2.}

\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}

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