solve by substitution method 6x-7y+25=0,5x-9y+1=0
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Given Equation is 6x - 7y + 25 = 0 ----- (1)
6x = 7y - 25
------ (2)
Given Equation is 5x - 9y + 1 = 0 ----- (3)
Substitute (2) in (3), we get.
5(7y - 25) - 54y = -6
35y - 125 - 54y = -6
-19y - 125 = -6
-19y = 119
y = -119/19.
Substitute y = -119/19 in (1), we get
6x - 7y + 25 = 0
6x - 7(-119/19) + 25 = 0
6x + 833/19 + 25 = 0
Therefore x = -218/19 and y = -119/19.
Hope this helps!
6x = 7y - 25
------ (2)
Given Equation is 5x - 9y + 1 = 0 ----- (3)
Substitute (2) in (3), we get.
5(7y - 25) - 54y = -6
35y - 125 - 54y = -6
-19y - 125 = -6
-19y = 119
y = -119/19.
Substitute y = -119/19 in (1), we get
6x - 7y + 25 = 0
6x - 7(-119/19) + 25 = 0
6x + 833/19 + 25 = 0
Therefore x = -218/19 and y = -119/19.
Hope this helps!
siddhartharao77:
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