Math, asked by krinajoshi04p5kzdu, 1 year ago

solve by substitution method 6x-7y+25=0,5x-9y+1=0

Answers

Answered by siddhartharao77
10
Given Equation is 6x - 7y + 25 = 0  ----- (1)

6x = 7y - 25

x =  \frac{7y - 25}{6}    ------ (2)

Given Equation is 5x - 9y + 1 = 0   ----- (3)

Substitute (2) in (3), we get.

5( \frac{7y - 25}{6} ) - 9y + 1 = 0

5( \frac{7y - 25}{6}) - 9y = -1

5(7y - 25) - 54y = -6

35y - 125 - 54y = -6

-19y - 125 = -6

-19y = 119

y = -119/19.


Substitute y = -119/19 in (1), we get

6x - 7y + 25 = 0

6x - 7(-119/19) + 25 = 0

6x + 833/19 + 25 = 0

6x +  \frac{19 * 25 + 833}{19} = 0

6x +  \frac{1308}{19} = 0

6x = - \frac{1308}{19}

x = - \frac{1308}{19 * 6}

x = - \frac{1308}{114}

x = - \frac{218}{19}


Therefore x = -218/19 and y = -119/19.


Hope this helps!

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