Question

solve by synthetic division
(2m3-3m+10)÷(m-5)​

Answer 1

Answer:

Given

m−5

2m

2

−3m+10

Now (2m

2

−3m+10) can be written after dividing by (m−5) as

(2m

2

−3m+10)=((2m+7)×(m−5))+45

so 45 is remainder and (2m+7) is dividend.