solve by the method of completing the square 9 x square - 15 X + 6 is equal to zero
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6
9 x^2 - 15x + 6 = 0
9 x^2 - 9x - 6x + 6 = 0
9x ( x - 1 ) - 6 ( x -1 ) = 0
(9x - 6 ) ( x - 1) =0
(x - 1 ) =0
x = 1
(9x - 6 ) =0
x = 6 / 9 = 2 /3
9 x^2 - 9x - 6x + 6 = 0
9x ( x - 1 ) - 6 ( x -1 ) = 0
(9x - 6 ) ( x - 1) =0
(x - 1 ) =0
x = 1
(9x - 6 ) =0
x = 6 / 9 = 2 /3
Answered by
3
9x^2/9-15x/9+6/9
X^2 - 5x/3 +2/3
X^2-5x/3 +2/3+(5/6)^2 -(5/6)^2=0
×^2 -5x/3 +(5/6)^2 = -2/3 + (5/6)^2=0
(×-5/6)^2 = -2/6 + 25/36
(×-5/6)^2 = 1/36
×-5/6 = +_ 1/6 x-5/6=-1/6
X=2/3
×-5/6= +1/6
X=1
X^2 - 5x/3 +2/3
X^2-5x/3 +2/3+(5/6)^2 -(5/6)^2=0
×^2 -5x/3 +(5/6)^2 = -2/3 + (5/6)^2=0
(×-5/6)^2 = -2/6 + 25/36
(×-5/6)^2 = 1/36
×-5/6 = +_ 1/6 x-5/6=-1/6
X=2/3
×-5/6= +1/6
X=1
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