solve by the method of eliminationx-y=5;3x+2y=25
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x−y=5−−−(1)
3x+2y=25−−−(2)
3x−3y=25
3x+2y=25
_______________
+5y=+10
⇒5y=10
⇒y= 10/5
⇒y=2.
sub y=2 in (1)
x−y=5
⇒x−2=5
⇒x=5+2
⇒x=7
∴ x=7 and y=2.
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