Solve by the method of substitutions
3 x+ 2y = 3, 3y − 2x = 2
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Answer:
3x+ 2y = 3....(i)
3x = 3-2y
x = 3-2y/3
3y- 2x = 2.......(ii)
putting the value of x in eq. (ii)
3y - 2(3-2y/3) = 2
3y - 6 +6y/ 3 = 2
9y - 6+ 6y = 6
9y+6y = 6+ 6
15y = 12
y = 12/15
y = 4/5
putting the value of y in eq. (i)
3x + 2y =3
3x = 3-2y
3x = 3-2(4/5)
3x = 3- 8/5
3x = 15 - 8 /5
3x = 7/5
x = 7/5*1/3
x = 7/ 15
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