Question

solve by the transposition method x/2+3/4=7/8​

Answer 1

$\bf{\underline{\red{QUESTION:-}}}$

solve by the transposition method x/2+3/4=7/8.

$\bf{\underline{\red{SOLUTION:-}}}$

$\bf →\frac{x}{2} + \frac{3}{4}=7/8$

• Using transposition method

$\bf \large→ \frac{x}{2} + \frac{3}{4} - \frac{7}{8}=0$

$\sf \large→ \frac{4x + 6 - 7}{8}=0$

$\sf →\frac{4x - 1}{8} = 0$

$\sf → 4x - 1 = 0 × 8$

$\sf → 4x - 1 = 0$

$\sf → 4x = 1$

$\sf → x = -4 + 1$

$\sf → x = -3$

$\bf{\underline{\red{HENCE:-}}}$

• The required value of X is -3

Answer 2

Using transposition method

=0→2x+43−87=0

→84x+6−7=0

→84x−1=0

→ 4x - 1 = 0 × 8

→4x−1=0×8

→4x−1=0

→4x=1

→x=−4+1

→x=−3

HENCE:−

HENCE:−The required value of X is -3