solve by trick
find sum without adding 1+3+5+7+9+11+13+15+17+19+21=
ankit1092:
hu
Answers
Answered by
3
Answer:
using Formula... Sn = n/2(a+l)
where a = first no
l = last no .
n = no of terms.
S11 = 11/2(1+21)= 11/2 ×22 = 121
the answer will be 121.
hope it helps you.... brainliest
Answered by
2
Step-by-step explanation:
Hello friend,
This is possible by arithmetic progression.
a=1
d=2
a(n)=19
a+(n-1)d=19
1+(n-1)2=19
n-1=18/2
n=10
S(n)=n[2a+(n-1)d]/2=10[2×1+(10-1)2]/2=5[2+18]=100
So, answer is 100.
hope it helps
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