solve by using cross multiplication method ...
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The solution of system of equation x=ab and y=ab
Step-by-step explanation:
Given: System of equation
\frac{b}{a}x+\frac{a}{b}y=a^2+b^2abx+bay=a2+b2 ---------(1)
x+y=2abx+y=2ab -----------(2)
Using elimination method to solve for x and y
Multiply second equation by -b/a to eliminate x
-\frac{b}{a}x-\frac{b}{a}y=-\frac{b}{a}\cdot 2ab−abx−aby=−ab⋅2ab
\frac{b}{a}x+\frac{a}{b}y=a^2+b^2abx+bay=a2+b2
Add both equation to eliminate x
\frac{a}{b}y-\frac{b}{a}y=a^2+b^2-\frac{b}{a}\cdot 2abbay−aby=a2+b2−ab⋅2ab
y(\dfrac{a^2-b^2}{ab})=a^2-b^2y(aba2−b2)=a2−b2
y=aby=ab
Substitute y=ab into equation (2)
x+ab=2abx+ab=2ab
x=abx=ab
Hence, The solution of system of equation x=ab and y=ab
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