Question

Solve by using formula 4 x² - 2 x-2x -1 =0 ​

Answer 1

Answer:

hey friend here is your answer..

$4 {x}^{2} - 2x - 2x - 1 = 0 \\ 4 {x}^{2} - 4x - 1 = 0 \\ we \: know \: that \: \\ x = \frac{ - b \frac{ + }{ } \sqrt{ {b}^{2} - 4ac} }{2a} \\ so...a = 4 \: \: b = - 4 \: \: \: c = - 1 \\ x = \frac{ - ( - 4) \frac{ + }{} \sqrt{ { - 4}^{2} - 4 \times 4 \times - 1} }{2 \times 4} \\ x = \frac{4 \frac{ + }{} \sqrt{16 + 16} }{8} \\ x = \frac{4 \frac{ + }{} \sqrt{32} }{8} \\ x = \frac{4 \frac{ + }{} \sqrt{16 \times 2} }{8} \\ x = \frac{4 \frac{ + }{}4 \sqrt{2} }{8}$

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