Question

solve by using quadratic formula x square - 3 x + 1 = 0​

Answer 1

Answer:

${x}^{2} - 3x + 1 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4 \times 1 \times 1 } }{2 \times 1} \\ x = \frac{3± \sqrt{ 9 - 4 } }{2} \\ x = \frac{3± \sqrt{5} }{2} \\ \boxed{ \large x = \underline{ \underline{ \frac{3 + \sqrt{5} }{2}}} \: \: \: or \: \: \: x = \underline{ \underline{ \frac{3 - \sqrt{5} }{2} }}}$