Question

Solve by using quadratic formula x²+(x+2)² =290

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

$x^2+(x+2)^2=290\\2x^2+4x+4=290\\2x^2+4x-286=0\\x^2+2x-143=0\\x^2+13x-11x-143=0\\x(x+13)-11(x+13)=0\\(x-11)(x+13)=0\\x=11\\x=-13$

$Now \;\;for\;\;ax^2+bx+c=0\\x=\frac{-b+\sqrt{b^2-4ac}}{2a}\\x=\frac{-b-\sqrt{b^2-4ac}}{2a}\\here\\a=1\\b=2\\c=-143\\x=\frac{-2+\sqrt{4-4(1)(-143)}}{2(1)}=\frac{-2+\sqrt{576}}{2}=\frac{-2+24}{2}=11\\x=\frac{-2-\sqrt{4-4(1)(-143)}}{2(1)}=\frac{-2-\sqrt{576}}{2}=\frac{-2-24}{2}=-13$

Hope it Helps