solve by using substitution method 3x-5y-4=0 and 9x=2y+7 [ class 10]
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Answered by
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Heya !!!
3X - 5Y = 4----------(1)
9X - 2Y = 7-------------(2)
From EQUATION (1) we get,
3X - 5Y = 4
3X = 4+5Y
X = 4+5Y/3 -------------(3)
Putting the value of X in equation (2)
9X - 2Y = 7
9 × (4+5Y/3) - 2Y = 7
3(4+5Y) - 2Y = 7
12 + 15Y - 2Y = 7
13Y = 7 -12
13Y = -5
Y = -5/13
Putting the value of X in equation (3)
X = 4+5Y/3 => 3 + 5 × -5/13 = 3 - 25/13 /3
X = 39 - 25/13/3 = 14/13/3 => 14/13 × 1/3 => 14/9
HOPE IT WILL HELP YOU...... :-)
3X - 5Y = 4----------(1)
9X - 2Y = 7-------------(2)
From EQUATION (1) we get,
3X - 5Y = 4
3X = 4+5Y
X = 4+5Y/3 -------------(3)
Putting the value of X in equation (2)
9X - 2Y = 7
9 × (4+5Y/3) - 2Y = 7
3(4+5Y) - 2Y = 7
12 + 15Y - 2Y = 7
13Y = 7 -12
13Y = -5
Y = -5/13
Putting the value of X in equation (3)
X = 4+5Y/3 => 3 + 5 × -5/13 = 3 - 25/13 /3
X = 39 - 25/13/3 = 14/13/3 => 14/13 × 1/3 => 14/9
HOPE IT WILL HELP YOU...... :-)
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