Math, asked by mayankanand33p5xsql, 1 year ago

Solve by using suitable identity (i) (4x + 2y)^2

Answers

Answered by dishagaur748
1
(4x+2y)^2                                                                                                                in this , the identity we will use is: (a+b)^2=a^2+2ab+b^2                                     (4x+2y)^2=(4x)^2+2*4x*2y+(2y)^2 = 16x^2+16xy+4^2                                           I hope it helped you


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