Question

solve by using the quadratic formula : x^2+x-2=0​

Answer 1

Answer:

x^2+x-2=0

x^2-x+2x-2=0

x(x-1)+2(x-1)=0

(x-1)(x+2)

x=1 or -2

Answer 2

Step-by-step explanation:

$x {}^{2} + x - 2 = 0$

$x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{2a}$

$a = 1$

$b = 1$

$c = - 2$

$x = \frac{ - 1 + - \sqrt{1 + 8} }{2}$

$x = \frac{1 + - 3}{2}$

$x = \frac{1 + 3}{2} \\ x = \frac{1 - 3}{2}$

$x = 2 \\ x = - 1$

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