solve cos^2A+cosA=sin^2A
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HOPE THIS HELPS YOU...
=> cos²A + cos A = sin²A. [since cos²x + sin²x =1]
=> 1 - sin²A + cos A = sin²A
=> cos A = 2sin²A - 1. [since cos²x + sin²x =1]
=> cos A = 2cos²A
=> cos A = 2.cos A .cos A
=> 1 = 2.cos A
=> cos A = 1/2
=> A = 60°
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
HOPE THIS HELPS YOU...
=> cos²A + cos A = sin²A. [since cos²x + sin²x =1]
=> 1 - sin²A + cos A = sin²A
=> cos A = 2sin²A - 1. [since cos²x + sin²x =1]
=> cos A = 2cos²A
=> cos A = 2.cos A .cos A
=> 1 = 2.cos A
=> cos A = 1/2
=> A = 60°
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
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