Solve
cot2A (secA-1)/1+sinA - sec2A(1-sinA)/1+secA
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3
Answer:
L.H.S = cot^2A( secA - 1 )/1+sinA
=1/tan^2x ( secA - 1) / (1+ sinA )
= ( secA-1) /( 1+ sinA)(sec^2A - 1)
= secA -1)/( 1+sinA) ( secA- 1) ( secA
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