Question

SOLVE d/dt (4 t ^-10 + 10 t ^ -4 + 10 t ) by derivation method. PLEASE DON'T POST IRRELEVANT ANSWERS WRONG ANSWER WILL BE REPORTED​

Answer 1

Explanation:

$\frac{d}{dt} (4t {}^{ - 10} + 10 {t}^{ - 4} + 10t) \\ \\ \\ = ( - 10.4.t {}^{ (- 10 - 1)} ) + ( -4 .10. {t}^{( - 4 - 1)} ) + 10 {t}^{1 - 1} \\ \\ \\ = - 40 {t}^{ - 11} - 40 {t}^{ - 5} + 10 \\ \\ \\ formula \: \: \: \: - \: \: \: \frac{d}{dx} (x {}^{2} ) = {x}^{2 - 1} = x$