solve (D2+9)y = cos2x
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Answer:
Ans is y=A cos3x+B sin3x+(1/5) cos2x
Step-by-step explanation:
D^2+9=cos2x
To find A. E
m^2+9=0, m=+3i, -3i
A. E y=A cos3x+B sin3x
To find P. I
y=1/(D^2+9) cos2x, on solving
y=1/(-2*2+9) cos2x=1/5cos2x
y=A.E+P.I
y=A cos3x+B sin3x+(1/5) cos2x
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