Question

solve..... don't spam​

Answer 1

Step-by-step explanation:

Plz refer to the above attachment

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Thank you

Answer 2

Step-by-step explanation:

(2/x+y)^2 + (x-y/2)^2 - 1 = 0

LHS step :

= (4)/(x+y)^2 + (x-y)^2/4 - 1

= [16+{(x-y)(x+y)}^2 - 4(x+y)^2]/ [4(x+y)^2]

= [16 + {(2cosecA)(2cos A)}^2 - 16 cosec^2A ] / [16 cosec^2A]

= [16 + {16 cos^2A.cosec^2} - 16cosec^2A ] / [16 cosec^2A]

= [1+cot^2A-cosec^2A]/ cosec^2A

= [ 1 - 1 ] / cosec^2 A

= 0

then LHS = RHS