Question

solve each of the following equatins by trial and direct method 8× +2=10×​

Answer 1

8x+2 = 10x

Trial method

Let's assume value of x as 1

∴ 8(1) + 2 = 10 (1)

=> 8 + 2 = 10

=> 10 = 10

=> LHS = RHS

Hence value of x is 1

Direct method

8x + 2 = 10

8x = 10 - 2

8x = 8

x = 8 / 8

x = 1

Answer 2

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• Trial method

→ When x=1

→ 8 (1) + 2 = 10 (1)

→ 10=10

→ Therefore x can be 1

• By Direct method

→ 8x + 2 = 10

→ 8x = 8

→ x = 1

Hence Solved