Math, asked by StarTbia, 1 year ago

Solve each of the following system of equations by elimination method.

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Answered by rohitkumargupta
1
HELLO DEAR,

x + y/2 = 4 , x/3 + 2y = 5

2x + y = 8-------------( 1 )
x + 6y = 15--------------( 2 )


FROM ------( 1 ) & -------( 2 )
multiply by (2) in --- ( 1 )

2x + y = 8
2x + 12y = 30
----------------------
-11y = -22

Y = 2 [ put in ----( 1 )]

2x + 2 = 8

2x = 6

x = 3 , y = 2


I HOPE ITS HELP YOU DEAR,
THANKS
Answered by Robin0071
0
Solution:-

given by :-
x+y/2 = 4

2x+y = 8 .........(1)

x/3 +2y = 5

x+6y = 15.........(2)

multiply by in eq(2) by 2. and substracting in eq(1)

2x+y = 8.......(1)
2x+12y = 30........(2)
- - -
________________

-11y = -22

y = 2

put y's value in eq(1)

2x + 2 = 8

2x = 8-2

x = 3


here (x , y) =(3,2) ans

☆i hope its help☆




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