Question

Solve each of the following systems of equations by the method of cross-multiplication:
5ax+6by=283ax+4by=18

Answer 1

Step-by-step explanation:

hence hope it helps you

Answer 2

Answer :

Given equations are

5ax + 6by = 28 ...(i)

3ax + 4by = 18 ...(ii)

Now, multiplying (i) by 3 and (ii) by 5, we get

15ax + 18by = 84

15ax + 20by = 90

On subtraction, we get

2by = 6

or, y = 3/b

Now, putting y = 3/b in (i), we get

5ax + 6b (3/b) = 28

or, 5ax + 18 = 28

or, 5ax = 28 - 18

or, 5ax = 10

or, x = 2/a

Therefore, the required solution be

x = 2/a and y = 3/b

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