Solve each of the following systems of equations by the method of cross-multiplication:
bx+cy=a+b ax(1/a-b - 1/a+b)+cy(1/b-a - 1/b+a)=2a/a+b
Answers
x = a/b , y = b/c
Step-by-step explanation:
bx+cy=a+b
ax(1/a-b - 1/a+b)+cy(1/b-a - 1/b+a)=2a/a+b
=> ax(2b)/(a² - b²) + cy(2a)/(b² - a²) = 2a/(a + b)
=> 2abx /(a - b) - 2acy/(a - b) = 2a
=> bx - cy = a - b
bx+cy=a+b
bx - cy = a - b
Adding both
=> 2bx = 2a
=> x = a/b
2cy = 2b
=> y = b/c
x = a/b , y = b/c
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Answer:
x = a/b , y = b/c
Step-by-step explanation:
bx+cy=a+b
ax(1/a-b - 1/a+b)+cy(1/b-a - 1/b+a)=2a/a+b
=> ax(2b)/(a² - b²) + cy(2a)/(b² - a²) = 2a/(a + b)
=> 2abx /(a - b) - 2acy/(a - b) = 2a
=> bx - cy = a - b
bx+cy=a+b
bx - cy = a - b
Adding both
=> 2bx = 2a
=> x = a/b
2cy = 2b
=> y = b/c
x = a/b , y = b/c