Question

Solve each quadratic equation by factoring. 6n^2-18n-18=6

Answer 1

6n²-18n-18-6=0

6n²-18n-24=0

n²-3n-4=0

n²-4n+n-4=0

n(n-4)+1(n-4)=0

(n+1)(n+4)=0

Answer 2

$Hey \: \: there !!$
We have , ➯

6n² - 18n - 18 = 6



∵ It is an Quadratic equation , Need to solve it by Factorization method ,
so ,


➱ 6n² - 18n -18 - 6 = 0

➱ 6 ( n² - 3n -3 -1. ) = 0

➱ n² - 3n - 4 = 0

Splitting it now such that when multiply first term and last term we get as the sum of the middle term



[ Here we can see , first and last term 1 × 4 = 4 and Middle term will be , - 4n + n or 4 ×1 = 4
which is equal to the product of first and last term ]


➱ n² -4n + n -4 = 0



➱( n² - 4n ) + ( n-4)


➱ n ( n- 4) + 1 ( n -4)



➱( n + 1) ( n -4 )

Further doing it to get , Its root

➱ n = 1 , 4

➤ Hope this would help you ➤