Solve equation By^2+Cy+A=0 by completing square method. Dont give any silly answer.
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BY^2+CY+A=0
B(Y^2+C/BY+A/B)=0
Y^2+C/BY+A/B=0
Y^2+C/BY+A/B+C^2/4B^2-C^2/4B^2=0
(Y+C/2B)^2=C^2/4B^2-A/B
(Y+C/2B)^2=(C^2-4AB)/4B^2
Y+C/2B=+/-ROOT(C^2-4AB/4B^2)
Y= -C/2B+/-ROOT(C^2-4AB/4B^2)
B(Y^2+C/BY+A/B)=0
Y^2+C/BY+A/B=0
Y^2+C/BY+A/B+C^2/4B^2-C^2/4B^2=0
(Y+C/2B)^2=C^2/4B^2-A/B
(Y+C/2B)^2=(C^2-4AB)/4B^2
Y+C/2B=+/-ROOT(C^2-4AB/4B^2)
Y= -C/2B+/-ROOT(C^2-4AB/4B^2)
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