Question

solve equation x^2+2√3x+3=0 using formula​

Answer 1

Answer:

The first term is, x2 its coefficient is 1 .

The middle term is, -3x its coefficient is -3 .

The last term, "the constant", is +3

Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3

Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -3 .

-3 + -1 = -4

-1 + -3 = -4

1 + 3 = 4

3 + 1 = 4

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step 1 :

x2 - 3x + 3 = 0

Answer 2

Answer:

Step-by-step explanation:

Here in this quadratic eqn, a=1, b=2root3, c=3

Quadratic formula: (-b+square root of b^2-4ac/2a or -b-square root of b^2-4ac/2a)

Discriminant(D)= b^2-4ac

=> 12-12= 0...

Since, D=0, the gn quad.eqn has 2  equal roots,

i.e, -b/2a= -2root3/2

=> -root3..........