Question

solve equations by completing method :√5x²+9x+4√5=0​

Answer 1

Answer:

Given √5x^2 +9x+4√5= 0. It is in the form of ax^2+ bx+c= 0. Where a= √5, b= 9, c= 4√5. Now it is in the form of quadratic equation, x= -b±√(b^2-4ac)/2a. x= -9±√[ 81-4(√5)(4√5)]/ 2√5. x= -9±√( 81-80) / 2√5, x= -9±√( 1)/2√5. x= (-9±1)/2√5. x= (-9-1)/ 2√5 and x= (-9+1)/2√5. x= -√5, -4√5/5. Hence the values of x are -√5, -4√5/5. Hope this helps you.