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ANSWER
According to Henry's law, the solubility of gas in a liquid is directly proportional to the pressure of the gas.
X=K
h
×P
X is the mole fraction of gas, K
h
is the Henry's law constant and P is the partial pressure of the gas.
Also mole fraction of ethane will be directly proportional to its mass.
WP
′
=W
′
P
W is the mass of ethane in first solution and P is the partial pressure of ethane in first solution.
W
′
is the mass of ethane in second solution and P
′
is the partial pressure of ethane in second solution.
6.56×10
−3
×P
′
=5.00×10
−2
×1
P
′
=7.6
Hence, the partial pressure of gas will be 7.6 bar.
Answer:
According to Henry’s law
.m = k x p
Substituting the given values in the above equation.
We get
6.56 x10-3 = k x 1
Or
k = 6.56 x10-3
Now when m = 5 x 10-2,
Then again substituting the given values in Henry’s law equation,we get
5 x 10-2 = 6.56 x10-3 x p
Or
p = 7.62 bar