Question

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Answer 1

Hey mate!

In the given figure, two triangles are combined to form a hexagon.

We know that ;

Sum of all sides of triangle = 180°.

In ∆ABC , sum of all sides

$\angle A +\angle B + \angle C$ = 180°

Again,

In ∆DEF

$\angle D + \angle E +\angle F$ = 180°.

So, Sum of all the angles of the given figure =

$\angle A + \angle B + \angle C + \angle D + \angle E + \angle F$

=> 180° + 180°

=> 360°

Hence, the sum of all the angles of the given figure is $\bold{360°.}$

Thanks for the question!

☺☺☺

Answer 2

In the given figure, two triangles are combined to form a hexagon.  We know that ;  Sum of all sides of triangle = 180°.  In ∆ABC , sum of all sides   = 180°   Again,  In ∆DEF   = 180°.  So, Sum of all the angles of the given figure =     => 180° + 180°  => 360°  Hence, the sum of all the angles of the given figure is