Question

solve for Θ:
2 sin²Θ=1/2, 0°< Θ < 90°

Answer 1

Hi there !


$2 {sin}^{2}θ = \frac{1}{2} \\ \\ {sin}^{2}θ \: = \frac{1}{4}$
sinθ = 1/2 ( sinθ >0 for 0° <θ° < 90°)

θ = 30°

Thanks :)