Question

Solve for 30points : If alpha and beta are the zeroes of (x-l)(x-m)-n prove that l,m are zeroes of (x-alpha) (x-beta) +n.​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

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x – \alpha)(x – \beta)=c

x2 – (\alpha + \beta)x +\alpha \beta = c (eqn 1 )

also

(x-a)(x-b) +c=0

x2 – (a+b)x +ab + c = 0

\alpha +\beta =a+b

\alpha\beta = ab + c

now eqn 1 becomes

x2 – (a+b)x + ab + c = c

x2 – (a+b)x + ab = 0

and roots of this equation are a and b

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