Math, asked by thecookiesncreamyt, 3 months ago

Solve for (9/4) power x+1 ÷ (2/3) power 3x-1 = (3/2) power 11​

Answers

Answered by ManishShah98
2

question =  (\frac{9}{4})^{x + 1}  \div  (\frac{2}{3} )^{3x -  1}  =  (\frac{3}{2}) ^{11}  \\ solution. \\   (\frac{ {3}^{2} }{ {2}^{2} })^{x + 1}  \times   (\frac{3}{2} )^{3x -  1}  =  (\frac{3}{2}) ^{11} \\ ( \frac{3}{2} ) ^{2(x + 1)}  \times (\frac{3}{2} )^{3x -  1} = (\frac{3}{2}) ^{11} \\ ( \frac{3}{2} ) ^{2x + 2}  \times (\frac{3}{2} )^{3x -  1} = (\frac{3}{2}) ^{11} \\ formula =  {a}^{1}  \times  {a}^{1}  =  {a}^{1 + 1} . \\ ( \frac{3}{2} ) ^{(2x + 2 + 3x - 1)} = (\frac{3}{2}) ^{11} \\ (\frac{3}{2}) ^{5x + 1}  = (\frac{3}{2}) ^{11} \\ 5x + 1 = 11 \\ 5x = 11 - 1 \\ 5x = 10 \\ x =  \frac{10}{5}  \\ x = 2 \:  \: answer...

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