solve for a: (a-2)+1÷a-2=3 ;a is not equal to 2.
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(a-2) + 1/(a-2)= 3
(a-2)^2+1=3 (a-2)
a^2-4a+4+1=3-6a
a^2+2a+2=0
this is quadratic equation so we first find D=b^2-4ac
now,
D=4-8 <0
hence roots are imaginary so,
we can't find out real root
(a-2)^2+1=3 (a-2)
a^2-4a+4+1=3-6a
a^2+2a+2=0
this is quadratic equation so we first find D=b^2-4ac
now,
D=4-8 <0
hence roots are imaginary so,
we can't find out real root
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