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If the product of two fractions is 12/5 and their quotient is 3/5, then the sum of the two fractions is??
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Answered by
13
Let two number be x and y
→xy=12/5----(i)
→x/y=3/5---(ii)
Multiplication of eq.(i) and eq.(ii)
xy×x/y=(12/5)×3/5
x²=36/25
→x=6/5
xy=12/5
Now putting value of x in eq.(i)
(6/5)y=12/5
y=60/30
→y=2
Sum =>x+y
→(6/5)+(2)=>6+10/5=>16/5
→16/5 is the answer
→xy=12/5----(i)
→x/y=3/5---(ii)
Multiplication of eq.(i) and eq.(ii)
xy×x/y=(12/5)×3/5
x²=36/25
→x=6/5
xy=12/5
Now putting value of x in eq.(i)
(6/5)y=12/5
y=60/30
→y=2
Sum =>x+y
→(6/5)+(2)=>6+10/5=>16/5
→16/5 is the answer
Answered by
4
let the fractions be a/b and c/d.
Given,
a/b x c/d = 12/5==>a/b = 12d/5c
( a/b divided by c/d gives the quotient )
a/b x d/c = 3/5==>a/b = 3c/5d
=>12d/5c = 3c/5d
60d² = 15c²
c² = 4d²
c = 2d
=>a/b = 6/5
a/b + c/d = 6/5 + 2d/d
= 6/5 + 5
= (6+10)/5
= 16/5
I hope it helps
Given,
a/b x c/d = 12/5==>a/b = 12d/5c
( a/b divided by c/d gives the quotient )
a/b x d/c = 3/5==>a/b = 3c/5d
=>12d/5c = 3c/5d
60d² = 15c²
c² = 4d²
c = 2d
=>a/b = 6/5
a/b + c/d = 6/5 + 2d/d
= 6/5 + 5
= (6+10)/5
= 16/5
I hope it helps
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